If ${R_1}\,\,{\rm{and}}\,\,{R_2}$ be the resistances of the filaments of ${\rm{200}}\,\,{\rm{W}}$ and ${\rm{100}}\,\,{\rm{W}}$ electric bulbs operation at ${\rm{220}}\,\,{\rm{V}}$, then $\left( {\frac{{{R_1}}}{{{R_2}}}} \right)$ is

JEE PHYSICS MCQ: CURRENT ELECTRICITY

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Application +4 | -1

{R_1}\,\,\mathrm{and}\,\,{R_2}

be the resistances of the filaments of

\mathrm{200}\,\,\mathrm{W}

and

\mathrm{100}\,\,\mathrm{W}

electric bulbs operation at

\mathrm{220}\,\,\mathrm{V}

, then

\left( {\frac{{{R_1}}}{{{R_2}}}} \right)

View answer and explanation

Correct option: C

\mathrm{0}\mathrm{.5}

Option C (0.5) is correct because the ratio of resistances is inversely proportional to the ratio of power, given the voltage is constant.

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\mathrm{\rho }

3\,\,{\mathrm{m}^3}

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4.7\,\, \times \,\,{10^6}\,\,\mathrm{\Omega }\,\, \pm \,\,5\,\,\%

22.5\,cm