Back to MECHANICAL PROPERTIES OF SOLIDS

JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF SOLIDS

1 Medium

1 of 1

Application +4 | -1

The length of a metal wire is

{l_1}

, when the tension in it is

{T_1}

and is

{l_2}

when the tension is

{T_{2.}}

The natural length of the wire is

View answer and explanation

Correct option: B

\frac{{{l_1}{T_2} - {l_2}{T_1}}}{{{T_2} - {T_1}}}

The correct answer is B (

\frac{{{l_1}{T_2} - {l_2}{T_1}}}{{{T_2} - {T_1}}}

) because it represents the natural length derived from the relationship between tension, length, and Young's modulus.

More Questions from MECHANICAL PROPERTIES OF SOLIDS

Practice All Chapter MCQs →

A wire is stretched under a force. If the wire suddenly snaps the temperature of the wire The increases in length is

l

of a wire of length

L

by the longitudinal stress. Then the stress is proportional to A steel wire of length

l

and cross sectional area

\mathrm{A}

is stretched by

1 \mathrm{~cm}

under a given load. When the same load is applied to another steel wire of double its length and half of its cross section area, the amount of stretching (extension) is Assertion: From the relation

Y=\frac{F l}{A \Delta l},

we can say that, if length of a wire is doubled, its Young's modulus of elasticity will also becomes two times.

Reason: Modulus of elasticity is a material property. A wire can be broken by applying a load of 200 N. The force required to break another wire of the same length and same material, but double in diameter, is Assertion(A): If radius of cylindrical wire is doubled, then this wire can bear four times stress.

Reason(R): By doubling the radius, area of cross-section will become four times.