JEE CHEMISTRY MCQ: HYDROCARBONS

1 Medium

1 of 1

Understanding +4 | -1

Propene and propyne can be distinguished by

View answer and explanation

Correct option: C

Tollen's reagent

Option C (Tollen's reagent) is correct because propyne, being a terminal alkyne, reacts with Tollen's reagent to form a precipitate, while propene does not.

More Questions from HYDROCARBONS

Practice All Chapter MCQs →

\mathrm{Ca}{\mathrm{C}_2} + {\mathrm{H}_2}\mathrm{O} \to X\xrightarrow{{{\mathrm{O}_3}/\frac{{{\mathrm{H}_2}\mathrm{O}}}{{\mathrm{O}{\mathrm{H}^ + }}}}}\mathrm{HCOOH} + \mathrm{HCOOH},X\;\mathrm{is}

In benzene, there is a delocalisation of π-electrons. Hence, each π-electron is attached by….carbon nuclei. Which statement is false? Assertion (A) In comparison to ethyl chloride, it is not easy to carry outnucleophilic substitution on vinyl chloride.

Reason (R) Vinyl group is an electron donating. If 2-oxopropanal and methanal are obtained by the reductive ozonolysis of compound (A), then the number of

\sigma

-bonds presents in Fischer-Tropsch process is used in the manufacture of: