Back to 14 TH GROUP ELEMENTS (P-BLOCK)
JEE CHEMISTRY MCQ: 14 TH GROUP ELEMENTS (P-BLOCK)
1
Easy
1 of 1
Understanding
+4 | -1
Ordinary sand is attacked by:
View answer and explanation
Correct option: C
hot KOH
The correct answer is C (hot KOH) because silicon dioxide (sand) reacts with hot potassium hydroxide to form potassium silicate and water.
More Questions from 14 TH GROUP ELEMENTS (P-BLOCK)
Practice All Chapter MCQs →
Which of the following does not exist
Newton’s alloy contains :
Which is pyrosilicate :-
Commercially important ore of lead is:
Assertion: is known but is not
Reason: Size of fluorine is small and its lone pair of electrons interacts with -orbitals of strongly. The correct statement with respect to carbon monoxide is:
Reason: Size of fluorine is small and its lone pair of electrons interacts with -orbitals of strongly. The correct statement with respect to carbon monoxide is: