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JEE MATHEMATICS MCQ: FUNCTIONS

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If f(x)=acos⁡(bx+c)+df(x)=a \cos (b x+c)+d, then range of f(x)f(x) is
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Correct option: D
[d−a,d+a][d-a, d+a]
Option D ([d−a,d+a][d-a, d+a]) is correct because the range of cos⁡(bx+c)\cos(bx+c) is [-1, 1], so the range of acos⁡(bx+c)a\cos(bx+c) is [-a, a], and adding d shifts the range to [d-a, d+a].

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