If $x>0, y>0$ and $x>y$, then $\tan ^{-1}(x / y)+\tan ^{-1}[(x+$ $y) /(x-y)]$ is equal to:

JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1

x>0, y>0

and

x>y

, then

\tan ^{-1}(x / y)+\tan ^{-1}[(x+

y) /(x-y)]

is equal to:

View answer and explanation

Correct option: C

3 \pi / 4

Option C (

\frac{{3 \pi}}{{4}}

) is correct because the given expression simplifies to

\pi + \tan^{{-1}}(-1)

under the given conditions, which equals

\frac{{3\pi}}{{4}}

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