NEET UG PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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A charged particle of mass

5 \times {10^{ - 5}}kg

is held stationary in space by placing it in an electric field of strength

{10^7}N{C^{ - 1}}

directed vertically downwards. The charge on the particle is

View answer and explanation

Correct option: B

- 5 \times {10^{ - 5}}\mu C

Option B (

- 5 \times {10^{ - 5}}\mu C

) is correct because the charge is calculated by equating the electric force to the gravitational force and considering the direction of the electric field.

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The ratio of magnitude of electric displacement (D) and electric field (E) is Gauss’s Law is valid for In hydrogen like system the ratio of coulombian force and gravitational force between an electron and a proton is in the order of: Statement-1:

\overrightarrow{{E}}

in outside velocity of a conductor depends only on the local charge density

\alpha

.
Statement-2:

\overrightarrow{{E}}

in outside vicinity of a conductor is given by

\frac{\sigma}{\varepsilon_0}

. Two charges each of 1 coulomb are at a distance 1

km

apart the force between them is

P \times 10^3

then value of

{P}

is Electric field due to point charge depends on distance

r