The maximum value of $\sin (\cos x)$ is

$\sin \left(\frac{1}{\sqrt{2}}\right)$

$\sin \left(\frac{\sqrt{3}}{2}\right)$

JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

1 of 1

Analyzing +4 | -1

The maximum value of

\sin (\cos x)

View answer and explanation

Correct option: A

\sin 1

Option A (

\sin 1

) is correct because the maximum value of

\cos x

is 1, and

\sin x

is increasing on

[-1, 1]

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