NEET UG PHYSICS MCQ: ELECTROMAGNETIC WAVES

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Application +4 | -1

Light with energy flux of

24\,w/{m^2}

is incident on a well polished disc of radios 3.5 cm for one hour. The momentum transferred to the disc is [in kgm

{s^{ - 1}}

]

View answer and explanation

Correct option: B

2.2 \times {10^{ - 6}}

Option B (

2.2 \times {10^{ - 6}}

) is correct because it is the momentum transferred calculated using the formula

p = (2UA)/c

for a reflecting surface.

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{E_X}

{E_R}

{E_M}

60\,\,\frac{V}{m}

{E_1} = {E_{01}}\hat x\cos \left[ {2\pi v\left( {\frac{z}{c} - t} \right)} \right]

{E_2} = {E_{02}}\hat x\cos \left[ {k\left( {2z - ct} \right)} \right]

{\varepsilon _{{r_1}}}

{\varepsilon _{{r_2}}}

E = 50\sin \,(500x - 10 \times {10^{10}}t)\,v/m.

c

\mathrm{\varepsilon }

\mathrm{\mu }

\sqrt {\frac{\mathrm{\mu }}{\mathrm{\varepsilon }}}