The number of solutions of the equation ${x^3} + {x^2} + 4x + 2\,\,\sin \,\,x = 0\,\,{\rm{in}}\,\;0 \le \,\,x\,\, \le \,\,2\pi $ is

JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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The number of solutions of the equation

{x^3} + {x^2} + 4x + 2\,\,\sin \,\,x = 0\,\,\mathrm{in}\,\;0 \le \,\,x\,\, \le \,\,2\pi

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Correct option: B

One

Option B (One) is correct because x=0 is the only solution that satisfies the given equation in the specified interval.

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