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JEE MATHEMATICS MCQ: STRAIGHT LINES

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Analyzing +4 | -1
For a>0,b>0,c>0a>0, b>0, c>0, the distance between (1,1)(1,1) and the point of intersection of the lines ax+by+c=0a x+b y+c=0 and bx+ay+c=0b x+a y+c=0 is less than 222 \sqrt{2}. Then,
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Correct option: A
a+b−c>0a + b - c > 0
Option A (a+b−c>0a + b - c > 0) is correct because it is derived from the distance condition between the point of intersection and (1,1) being less than 222\sqrt{2}.

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