$\mathop {\lim }\limits_{n \to \infty } \frac{{{1^2} + {2^2} + {3^2} + ... + {n^2}}}{{{n^3}}}$ is equal to

JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Application +4 | -1

\lim\limits_{n \to \infty } \frac{{{1^2} + {2^2} + {3^2} + ... + {n^2}}}{{{n^3}}}

is equal to

View answer and explanation

Correct option: C

\frac{1}{3}

Option C (

\frac{1}{3}

) is correct because the limit of the sum of squares divided by n³ is 1/3.

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