The solution of $\tan \,\,2\theta \,\,\tan \,\,\theta = 1$ is ${\rm{22}}$

$\left( {4n\,\, \pm \,\,1} \right)\frac{\pi }{6}$

$\left( {2n\,\, + \,\,\pi } \right)\frac{\pi }{6}$

JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1

The solution of

\tan \,\,2\theta \,\,\tan \,\,\theta = 1

\mathrm{22}

View answer and explanation

Correct option: B

\left( {6n\,\, \pm \,\,1} \right)\frac{\pi }{6}

Option B is the correct solution because it represents the general solution to the trigonometric equation

\tan 2\theta \tan \theta = 1

after simplification and solving for

\theta

Practice All Chapter MCQs →

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\mathrm{X}

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