JEE MATHEMATICS MCQ: PERMUTATIONS

1 Medium

1 of 1

Application +4 | -1

Ten persons, amongst whom are

A,B

and

C

to speak at a function. The number of ways in which it can be done, if

A

wants to speak before

B

and

B

wants to speak before

C

View answer and explanation

Correct option: A

\frac{{10!}}{6}

Option A (

\frac{{10!}}{6}

) is correct because A, B, and C can be arranged in 3! = 6 ways, but only one of these ways (A before B before C) is desired, so we divide the total permutations by 6.

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r

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letterboxes in a town is The number of four-digit numbers that can be made with the digits

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\left( {m + n} \right)

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n

at another. The number of ways of arranging the guests is