JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

1 of 1

Application +4 | -1

In a triangle vertex angles are

A,\;B,\;C

and side

BC

are given. The area of

\Delta ABC

View answer and explanation

Correct option: D

\frac{1}{2}.\frac{{{a^2}\sin B\sin C}}{{\sin A}}

Option D (

\frac{1}{2}.\frac{{{a^2}\sin B\sin C}}{{\sin A}}

) is correct because it represents the area of the triangle in terms of one side and all three angles, derived using the sine rule.

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k

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a = \left( {b - c} \right)\sec \theta

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A

2 s