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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
lim⁡n→∞∑k=1nnn2+k2x2,x>0\lim \limits_{{n \rightarrow \infty}} \sum\limits_{{k=1}}^n \frac{n}{n^2+k^2 x^2}, x>0 is equal to
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Correct option: C
tan⁡−1(x)x\frac{\tan ^{-1}(x)}{x}
Option C is correct because converting the limit to an integral and evaluating it results in tan⁡−1(x)x\frac{\tan^{-1}(x)}{x}.

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