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JEE PHYSICS MCQ: NUCLEI

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Application +4 | -1
The half-life of radioactive Radon is 3.8  days\mathrm{3}.\mathrm{8}\,\,\mathrm{days}. The time at the end of which (1/20\mathrm{1/20})th of the Radon sample will remain undecayed is (given log⁡10 e=0.4343{\log _{10}}\,e = 0.4343)
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Correct option: B
16.5 days\mathrm{16}\mathrm{.5 }\,\mathrm{days}
Option B (16.5 days\mathrm{16}\mathrm{.5 }\,\mathrm{days}) is correct because it is calculated using the half-life formula and the given logarithmic value.

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