JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Analyzing +4 | -1

\lim \limits_{{x \rightarrow 0}} \frac{a e^x-b \cos x+c e^{-x}}{x \sin x}=2

, then

a+b+c=

View answer and explanation

Correct option: B

Option B (4) is correct because the limit exists only when certain conditions are met, which leads to a system of equations that can be solved for

a+b+c

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