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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
∫0πxsin⁡3xdx=\int\limits_{0}^\pi x \sin ^3 x d x=
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Correct option: B
2π3\frac{2 \pi}{3}
Option B (2π3\frac{2 \pi}{3}) is correct because using the property ∫0af(x)dx=∫0af(a−x)dx\int_0^a f(x) dx = \int_0^a f(a-x) dx simplifies the integral, allowing for direct calculation.

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