An organic compound has an empirical formula ${\rm{(C}}{{\rm{H}}_2}{\rm{O)}}$ its vapour density is 45. The molecular formula of the compound is

${{\rm{C}}_3}{{\rm{H}}_6}{{\rm{O}}_3}$

${{\rm{C}}_2}{{\rm{H}}_5}{\rm{O}}$

${{\rm{C}}_2}{{\rm{H}}_2}{\rm{O}}$

JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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An organic compound has an empirical formula

\mathrm{(C}{\mathrm{H}_2}\mathrm{O)}

its vapour density is 45. The molecular formula of the compound is

View answer and explanation

Correct option: D

{\mathrm{C}_3}{\mathrm{H}_6}{\mathrm{O}_3}

Option D (

{\mathrm{C}_3}{\mathrm{H}_6}{\mathrm{O}_3}

) is correct because the molecular formula is determined by multiplying the empirical formula by a factor derived from the vapor density.