NEET UG PHYSICS MCQ: WORK-ENERGY-POWER

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A particle is moving in a circular path of radius a under the action of an attractive potential

U = - \frac{k}{{2{r^2}}}

Its total energy is

View answer and explanation

Correct option: C

Zero

The correct answer is C (Zero) because for a particle moving in a circular path under the given potential, the kinetic energy equals half the magnitude of the potential energy, resulting in a total energy of zero.

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