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NEET UG PHYSICS MCQ: WORK-ENERGY-POWER

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The position x of a particle of mass 2 kg moving along straight line is given as x=(t−2)2x = {\left( {t - 2} \right)^2}, where t is in second and x is in metre. The work done by the force in first 2s is
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Correct option: B
-16 J
Option B (-16 J) is correct because the work done is equal to the change in kinetic energy, calculated from the initial and final velocities.

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