JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Analyzing +4 | -1

The equation

e^{\sin x}-e^{-\sin x}-4=0

has :

View answer and explanation

Correct option: B

No real roots

The equation has no real roots because the value of

e^{\sin x}

cannot be negative or less than 1, and

\ln(2+\sqrt{5}) > 1

, which is outside the range of

\sin x

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\left[ {0,\;\,\frac{\pi }{2}} \right]

\left( {x,\,y} \right)

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\left( {\sqrt {{{\sin }^2} - \sin \,\,x + \frac{1}{2}} } \right){2^{{{\sec }^2}y}}\,\, \cdot \,\, \le 1

\mathrm{X}

\theta \rightarrow \frac{\pi}{2}

\sin x+\cos x=\frac{\sqrt{7}}{2}

x \in\left[0, \frac{\pi}{4}\right]

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\tan \frac{\pi}{5}+2 \tan \frac{2 \pi}{5}+4 \cot \frac{4 \pi}{5}

0 < x < \pi

\cos x+\sin x=\frac{1}{2}

\tan x