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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1
The value of the integral
∫410[x2]dx[x2−28x+196]+[x2], where [x]\int\limits_{4}^{10} \frac{\left[x^2\right] d x}{\left[x^2-28 x+196\right]+\left[x^2\right]} \text {, where }[x]
denotes the greatest integer less than or equal to x\mathrm{x}, is :
View answer and explanation
Correct option: D
3
Option D (3) is correct because the integral simplifies to 3 after using the property ∫abf(x)dx=∫abf(a+b−x)dx\int_a^b f(x) dx = \int_a^b f(a+b-x) dx.

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