Question

Consider a radioactive substance which decays, following the law of disintegration. At an instant $t_1$ its activity is $R$ and at time $t_2$ it becomes $\frac{1}{R}$. Find the average life of radioactive substance, if $t_2 > t_1$.

Accepted Answer

$\frac{\left(t_2-t_1\right)}{2 \ln (R)}$

Answer

$\frac{\left(t_2-t_1\right)}{2} \ln (R)$

Answer

$2 \ln (R)\left(t_2-t_1\right)$

Answer

$\frac{2\left(t_2-t_1\right)}{\ln (R)}$

JEE PHYSICS MCQ: NUCLEI

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