In the equation, $4M{\rm{\;}} + {\rm{\;}}8{\rm{C}}{{\rm{N}}^ - }{\rm{\;}} + {\rm{\;}}2{{\rm{H}}_2}{\rm{O\;}} + {\rm{\;}}{{\rm{O}}_2}{\rm{\;\;}} \to {\rm{\;}}4{\left[ {M{{\left( {{\rm{CN}}} \right)}_2}} \right]^ - }{\rm{\;}} + {\rm{\;}}4{\rm{O}}{{\rm{H}}^ - }$ Identify the metal $M$

JEE CHEMISTRY MCQ: d & f- BLOCK ELEMENTS

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Application +4 | -1

In the equation,

4M\mathrm{\;} + \mathrm{\;}8\mathrm{C}{\mathrm{N}^ - }\mathrm{\;} + \mathrm{\;}2{\mathrm{H}_2}\mathrm{O\;} + \mathrm{\;}{\mathrm{O}_2}\mathrm{\;\;} \to \mathrm{\;}4{\left[ {M{{\left( {\mathrm{CN}} \right)}_2}} \right]^ - }\mathrm{\;} + \mathrm{\;}4\mathrm{O}{\mathrm{H}^ - }

Identify the metal

M

View answer and explanation

Correct option: C

Silver

Option C (Silver) is correct because silver forms a complex with cyanide ions in the presence of oxygen and water, as shown in the cyanide process.