JEE PHYSICS MCQ: WAVES

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Application +4 | -1

The equation of a simple harmonic wave is given by

y = 6\,\,\sin \,\,2\pi \left( {2t - 0.1x} \right)

where x and y are in mm and t is in seconds. The phase difference between two particles 2 mm apart at any instant is

View answer and explanation

Correct option: B

72^\circ

Option B (

72^\circ

) is correct because the phase difference is calculated using the wave number and the distance between the particles.

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The source of sound generating a frequency of

3\,\,kHz

reaches an observer with a speed of

0.5

times, the velocity of sound in air. The frequency heard by the observer is A source of sound emits waves with frequency

f\mathrm{ }Hz

V\mathrm{ }m/sec

. Two observers move away from this source in opposite directions each with a speed

0.2\,\,V

relative to the source. The ratio of frequencies heard by the two observers will be Assertion: The wave function of a pulse is given by

y = \frac{3}{{{{\left( {2x + 3t} \right)}^2} + 4}},

it propagates in

(– \mathrm{ve}) \,x

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Reason: The given wave function is of the form

y = f(kx +\omega t),

which represent a wave travelling in negative

X

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0.01\,\,s

. the fundamental frequency is A rope

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long has a total mass of

245 \mathrm{~g}

. It is stretched with a constant tension of

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wt. If it is fixed at one end and shaken by hand at the other end, what frequency of shaking will make it break up into three vibrating segments? Take

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T

is the reverberation time of an auditorium of volume

V