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JEE PHYSICS MCQ: WAVES

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Analyzing +4 | -1
The mathematical form of three travelling waves are given by

y1=(2 cm)sin⁡(3x−6t),y2=(3 cm)sin⁡(4x−12t),  and y3=(4 cm)sin⁡(5x−11t)\begin{aligned} & y_1=(2 {~cm}) \sin (3 x-6 t), \\ & y_2=(3 {~cm}) \sin (4 x-12 t) \text {, } \\ & \text { and } y_3=(4 {~cm}) \sin (5 x-11 t) \\ \end{aligned}

of these waves,
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Correct option: D
Wave 2 has greatest wave speed and wave 3 has maximum transverse string speed
Option D (Wave 2 has greatest wave speed and wave 3 has maximum transverse string speed) is correct because wave speed is ω/k\omega/k and maximum transverse speed is AωA\omega.

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