Skip to main content
Back to STATISTICS

JEE MATHEMATICS MCQ: STATISTICS

1 Medium
1 of 1
Application +4 | -1
Let 9=x1<x2<…<x79=x_{1} < x_{2} < \ldots < x_{7} be in an A.P. with common difference dd. If the standard deviation of x1,x2…x7x_{1}, x_{2} \ldots x_{7} is 4 and the mean is xˉ\bar{x}, then xˉ+x6\bar{x}+x_{6} is equal to:
View answer and explanation
Correct option: B
34
Option B (34) is correct because it is the sum of the mean and the 6th term of the A.P., calculated using the given standard deviation.

More Questions from STATISTICS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.