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NEET UG PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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Analyzing +4 | -1
In van der Wall equation [P+aV2][V−b]=RT;P\left[P+\frac{a}{V^2}\right][V-b]=R T ; P is pressure, VV is volume, RR is universal gas constant and TT is temperature. The ratio of constants ab\frac{a}{b} is dimensionally equal to:
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Correct option: C
PVP V
Option C (PVP V) is correct because the term aV2\frac{a}{V^2} has the dimensions of pressure (P), and aa therefore has dimensions of PV2PV^2. The term bb has dimensions of volume (V). Thus, ab\frac{a}{b} has dimensions of PV2V=PV\frac{PV^2}{V} = PV.

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