If $S = \frac{1}{3}f{t^3},f$ has the dimensions of

$\left[ {{{\rm{M}}^0}{{\rm{L}}^{ - 1}}{{\rm{T}}^3}} \right]$

$\left[ {{\rm{ML}}{{\rm{T}}^{ - 3}}} \right]$

$\left[ {{{\rm{M}}^0}{{\rm{L}}^1}{{\rm{T}}^{ - 3}}} \right]$

$\left[ {{{\rm{M}}^0}{{\rm{L}}^{ - 1}}{{\rm{T}}^{ - 3}}} \right]$

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NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

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S = \frac{1}{3}f{t^3},f

has the dimensions of

View answer and explanation

Correct option: A

\left[ {{\mathrm{M}^0}{\mathrm{L}^{ - 1}}{\mathrm{T}^3}} \right]

Option C ([

{\mathrm{M}^0}{\mathrm{L}^1}{\mathrm{T}^{ - 3}}

]) is correct because it involves finding the dimensions of f from the equation

S = \frac{1}{3}f{t^3}

, where S is displacement and t is time. By rearranging the equation to solve for f and substituting the dimensions of S and t, we can find the dimensions of f.

NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

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