Question

Two vectors ${m{\vec A}}\,and\,{m{\vec B}}$ are inclined at an angle $	heta $. Now if the vectors are interchanged then the resultant turns through an angle $\beta $. Which of the following relation is true

Accepted Answer

$	an \frac{\alpha }{2} = {\left( {\frac{{A - B}}{{A + B}}} ight)^\;}	an \frac{{m{	heta }}}{2}$

Answer

$	an \frac{\alpha }{2} = {\left( {\frac{{A - B}}{{A + B}}} ight)^2}	an \frac{{m{	heta }}}{2}$

Answer

$	an \frac{\alpha }{2} = {\left( {\frac{{A - B}}{{A + B}}} ight)^2}\cot \frac{{m{	heta }}}{2}$

Answer

$	an \frac{\alpha }{2} = {\left( {\frac{{A - B}}{{A + B}}} ight)^\;}\cot \frac{{m{	heta }}}{2}$

NEET UG PHYSICS MCQ: MOTION IN PLANE

More Questions from MOTION IN PLANE