NEET UG CHEMISTRY MCQ: SOLID STATE

1 Easy

1 of 1

Application +4 | -1

A metal

X

crystallises in a face-centred cubic arrangement with the edge length

862 \mathrm{pm}

. What is the shortest separation of any two nuclei of the atom?

(\sqrt{2}=1.4)

View answer and explanation

Correct option: D

616 \mathrm{~pm}

Option D (616 pm) is correct because the shortest separation in an FCC lattice is half the face diagonal, which is calculated as

\frac{{\sqrt{2}}}{{2}}a

More Questions from SOLID STATE

Practice All Chapter MCQs →

\mathrm{C}{\mathrm{s}^ + }

\mathrm{C}{\mathrm{I}^ - }

\;0.181\,\,nm

A

B

A

Y