Bohr’s radius of 2nd orbit of ${\rm{B}}{{\rm{e}}^{3 + }}$ is equal to that of

2nd orbit of ${\rm{H}}{{\rm{e}}^ + }$

3rd orbit of ${\rm{L}}{{\rm{i}}^{2 + }}$

JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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Bohr’s radius of 2nd orbit of

\mathrm{B}{\mathrm{e}^{3 + }}

is equal to that of

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Correct option: D

First orbit of hydrogen

Option D (First orbit of hydrogen) is correct because the Bohr radius of the 2nd orbit of Be3+ is equal to the Bohr radius of the first orbit of hydrogen.

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