The value of the integral $\int\limits_{ - 1}^1 {\log ({\rm{x}} + \sqrt {{{\rm{x}}^2} + 1)} } \,d{\rm{x}}$ is

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1

The value of the integral

\int\limits_{ - 1}^1 {\log (\mathrm{x} + \sqrt {{\mathrm{x}^2} + 1)} } \,d\mathrm{x}

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Correct option: B

Option B (0) is correct because the integrand is an odd function, and the integral of an odd function over a symmetric interval is zero.

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