A magnet of length 0.1 m and pole strength ${10^{ - 4}}$ A-m is kept in a magnetic field of 30 Wb ${{\rm{m}}^{ - 2}}$ at an angle $30^\circ .$ The couple acting on it is ……..$ \times {10^{ - 4}}$ Nm.

JEE PHYSICS MCQ: MAGNETISM AND MATTER

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Application +4 | -1

A magnet of length 0.1 m and pole strength

{10^{ - 4}}

A-m is kept in a magnetic field of 30 Wb

{\mathrm{m}^{ - 2}}

at an angle

30^\circ .

The couple acting on it is ……..

\times {10^{ - 4}}

Nm.

View answer and explanation

Correct option: D

1.5

Option D (1.5) is correct because the torque is calculated using the formula

\tau = MB\sin{\theta}

, where M is the magnetic moment, B is the magnetic field, and

\theta

is the angle.

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