$\lim _\limits{x \rightarrow 0} \frac{\cos 2 x-\cos x}{\sin ^2 x}$ is

JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Application +4 | -1

\lim \limits_{{x \rightarrow 0}} \frac{\cos 2 x-\cos x}{\sin ^2 x}

View answer and explanation

Correct option: D

-\frac{3}{2}

The correct answer is D (-

\frac{3}{2}

) because applying L'Hôpital's rule twice to the limit yields the value -

\frac{3}{2}

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