JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

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Analyzing +4 | -1

The number of real solutions of

\sin e^x \cdot \cos e^x=2^{x-2}+2^{-x-2}

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Correct option: A

Option A (0) is correct because the equation

\sin e^x \cdot \cos e^x=2^{x-2}+2^{-x-2}

has no real solutions since the LHS is less than or equal to 1/2 and the RHS is greater than or equal to 1/2, and equality cannot hold.

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