NEET UG PHYSICS MCQ: ELECTROMAGNETIC WAVES

1 Easy

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Application +4 | -1

An electromagnetic wave has electric field given by

\vec{E}=(9.6 \hat{j}) \sin \left[2 \pi\left\{30 \times 10^6 t-\frac{1}{10} x\right\}\right], x

and

t

are in SI units. The maximum magnetic field is

View answer and explanation

Correct option: A

3.2 \times 10^{-9}

Option A (

3.2 \times 10^{-9}

) is correct because the maximum magnetic field is calculated using the relation

B_0 = \frac{E_0}{c}

, where c is the speed of light.

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{E_X}

{E_R}

{E_M}

60\,\,\frac{V}{m}

{E_1} = {E_{01}}\hat x\cos \left[ {2\pi v\left( {\frac{z}{c} - t} \right)} \right]

{E_2} = {E_{02}}\hat x\cos \left[ {k\left( {2z - ct} \right)} \right]

{\varepsilon _{{r_1}}}

{\varepsilon _{{r_2}}}

E = 50\sin \,(500x - 10 \times {10^{10}}t)\,v/m.

c

\mathrm{\varepsilon }

\mathrm{\mu }

\sqrt {\frac{\mathrm{\mu }}{\mathrm{\varepsilon }}}