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NEET UG PHYSICS MCQ: DUAL NATURE OF RADIATION AND MATTER

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The de-Broglie wavelength λ\lambda associated with an electron having kinetic energy EE is given by the expression
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Correct option: A
h2mE\frac{h}{{\sqrt {2mE} }}
Option A is correct because the de Broglie wavelength is given by λ = h/sqrt(2mE), where E is the kinetic energy.

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