JEE MATHEMATICS MCQ: MULTIPLE AND SUBMULTIPLE ANGLES

1 Easy

1 of 1

Application +4 | -1

\frac{{\mathrm{sin}\,\,\mathrm{\;}\left( {x + y} \right)}}{{\sin \,\,\;\left( {x - y} \right)}} = \frac{{a + b}}{{a - b}}

, then

\frac{{\tan \,\,x}}{{\tan \,\,y}}

is equal to

View answer and explanation

Correct option: B

\frac{a}{b}

Option B (

\frac{a}{b}

) is correct because by applying the componendo and dividendo rule and trigonometric identities, the ratio of tangents simplifies to

\frac{a}{b}

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