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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
The value of ∫0πxlog⁡(sin⁡x)dx\int\limits_{0}^\pi x \log (\sin x) \mathrm{d} x is (given that ∫0π/2log⁡sin⁡x dx=−π2log⁡2)\int\limits_{0}^{\pi / 2} \log \sin x \mathrm{~d} x=-\frac{\pi}{2} \log 2)
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Correct option: A
−π22log⁡2-\frac{\pi^2}{2} \log 2
Option B (6) is correct because by setting up equations based on the given information about pairs and triplets, we can solve for n.

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