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JEE PHYSICS MCQ: WAVE OPTICS

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In young's experiment light of wavelength 4800 A∘4800 ~\mathop {\text{A}}\limits^ \circ is used. If one slit is covered with glass of refractive index 1.41.4 and another slit is covered with a film of same thickness having refractive index 1.7,1.7, the centre fringe shifts to the position of 5th5^{\text {th}} bright fringe then find the thickness of film.
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Correct option: D
8×10−3 mm8 \times 10^{-3} \mathrm{~mm}
Option D (8×10−3 mm8 \times 10^{-3} \mathrm{~mm}) is correct because it is the thickness calculated using the formula for fringe shift due to introducing films of different refractive indices: t(μ1−μ2)=nλt(\mu_1 - \mu_2) = n\lambda.

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