JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1

Let

f

be a positive function. Let

I_1=\int_{1-k}^k(x) f(x(1-x)) d x ; I_2=\int_{1-k}^k f(x(1-x)) d x,

where

2 k-1>0

. Then,

\frac{I_2}{I_1}

View answer and explanation

Correct option: D

Option D (2) is correct because by using King's property and adding the integrals, we find that I2 is twice I1.

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