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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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If x=sin⁑(Ξ±βˆ’Ξ²)sin⁑(Ξ³βˆ’Ξ΄),  y=sin⁑(Ξ²βˆ’Ξ³)sin⁑(Ξ±βˆ’Ξ΄)x = \sin \left( {\alpha - \beta } \right)\sin \left( {\gamma - \delta } \right),\,\,y = \sin \left( {\beta - \gamma } \right)\sin \left( {\alpha - \delta } \right) and z=sin⁑(Ξ³βˆ’Ξ±)sin⁑(Ξ²βˆ’Ξ΄),z = \sin \left( {\gamma - \alpha } \right)\sin \left( {\beta - \delta } \right), then
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Correct option: A
x+y+z=0x+y+z=0
Option A (x+y+z=0x+y+z=0) is correct because when the expressions for x, y, and z are expanded and added, the terms cancel out, resulting in zero.

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The number of solutions of the equation sin⁑  xβ€‰β€‰β€…β€Šcos  3x=sin⁑  3x  cos⁑  5x\sin \,\,x\,\,\;cos\,\,3x = \sin \,\,3x\,\,\cos \,\,5x in [0,β€…β€Šβ€‰Ο€2]\left[ {0,\;\,\frac{\pi }{2}} \right] is The number of ordered pairs (x, y)\left( {x,\,y} \right) where x,  y∈[0,10]x,\,\,y \in \left[ {0,10} \right] satisfying (sin⁑2βˆ’sin⁑  x+12)2sec⁑2y  ⋅  ≀1\left( {\sqrt {{{\sin }^2} - \sin \,\,x + \frac{1}{2}} } \right){2^{{{\sec }^2}y}}\,\, \cdot \,\, \le 1 is Statement I: If slope of the tangent line is zero, then tangent line is perpendicular to the X\mathrm{X}-axis.

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