General solution of the equation $\cot \,\,{\rm{\theta }}\,\, - \,\,\tan \,\,{\rm{\theta }} = 2$ is

$\frac{{n\pi }}{2} \pm \frac{\pi }{8}$

JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

General solution of the equation

\cot \,\,\mathrm{\theta }\,\, - \,\,\tan \,\,\mathrm{\theta } = 2

View answer and explanation

Correct option: B

\frac{{n\pi }}{2} + \frac{\pi }{8}

Option B (

\frac{{n\pi }}{2} + \frac{\pi }{8}

) is correct because by simplifying the given equation using trigonometric identities, we get

\tan 2\theta = 1

, which leads to the general solution

\theta = \frac{{n\pi }}{2} + \frac{\pi }{8}

Practice All Chapter MCQs →

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