Skip to main content
Back to PARABOLA

JEE MATHEMATICS MCQ: PARABOLA

1 Easy
1 of 1
Application +4 | -1
The tangent to the parabola y2=4x{y^2} = 4x at the point where it intersects the circle x2+y2=5{x^2} + {y^2} = 5 in the first quadrant, passes through the point
View answer and explanation
Correct option: B
(34,74)\left( {\frac{3}{4},\frac{7}{4}} \right)
Option B ((34,74)\left( {\frac{3}{4},\frac{7}{4}} \right)) is correct because the tangent to the parabola at the point of intersection with the circle in the first quadrant passes through this point.

More Questions from PARABOLA

Practice All Chapter MCQs →
The equation of a common tangent to the parabolas y=x2y=x^2 and y=−(x−2)2y=-(x-2)^2 is A point PP moves such that slope of one tangent drawn from it to parabola y2=16xy^2=16 x is four times the slope of other tangent, then the length of latus rectum of the conic represented by locus of PP, is Let P,Q,RP,Q,R be three points on parabola y2=4x{y^2} = 4x and normal at PP and RR meet at QQ, then the locus of the mid-point of the chord PRPR is a parabola whose vertex is at The tangents at the end points of any chord through (1,0)(1,0) to the parabola y2+4x=8y^2+4 x=8 intersect The focus of the parabola x2=−16yx^2=-16 y is If II denotes the semi-latusrectum of the parabola y2=4ax{y^2} = 4ax and SPSP and SQSQ denote the segments of any focal chord PQ,SPQ,S being the focus, then SP,lSP,l and SQSQ are in the relation
Type at least 2 characters or jump directly:
🩺 NEET MCQs 🔬 JEE MCQs 🎯 JEE College Predictor Study guides 📊 Dashboard
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.

Continue with Free Account →