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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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The sum of nn terms of the series 51.2⋅13+72⋅3⋅132+93.4⋅133+114.5⋅134+…\frac{5}{1.2} \cdot \frac{1}{3}+\frac{7}{2 \cdot 3} \cdot \frac{1}{3^2}+\frac{9}{3.4} \cdot \frac{1}{3^3}+\frac{11}{4.5} \cdot \frac{1}{3^4}+\ldots. is:
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Correct option: A
1−1n+1⋅13n1-\frac{1}{n+1} \cdot \frac{1}{3^n}
The correct answer is A (1−1n+1⋅13n1-\frac{1}{n+1} \cdot \frac{1}{3^n}) because the sum of the series can be simplified and expressed in this form by decomposing the general term.

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