JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Medium

1 of 1

Application +4 | -1

The angle of intersection of the curves

y = {x^2},\;y = 7 - {x^3}

at (1, 1) is

View answer and explanation

Correct option: C

\pi /2

Option C (

\pi /2

) is correct because the product of the slopes of the tangents to the two curves at the point of intersection is -1, indicating perpendicularity.

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z