NEET UG PHYSICS MCQ: MOTION IN PLANE

1 Medium

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Application +4 | -1

\vec A.\vec B = \sqrt 3 \left| {\vec A \times \vec B} \right|

then angle between

\vec A

and

\vec B

will be

View answer and explanation

Correct option: A

\frac{\pi }{6}

Option A (

\frac{\pi }{6}

) is correct because it is derived from the relationship between the dot product and cross product magnitudes, where

\tan \theta = \frac{1}{\sqrt{3}}

More Questions from MOTION IN PLANE

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\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)